so you probably know that to get from concentration to pH or pOH, you use -log(concentration). To get from the pH or pOH to the concentration you have to do the reverse of this, which is 10 raised to the negative concentration. In this example, the pOH is 1.8, so 10^-1.8 will give you your concentration of 0.0158. I hope this helps!!
How did you get from the pOH = 1.80 to knowing the concentration of OH-?
so you probably know that to get from concentration to pH or pOH, you use -log(concentration). To get from the pH or pOH to the concentration you have to do the reverse of this, which is 10 raised to the negative concentration. In this example, the pOH is 1.8, so 10^-1.8 will give you your concentration of 0.0158. I hope this helps!!